export mypath=$dirname{"$0"}However you can't get absolute path with this method, it get the relative path of $0
Someone use this code to probe the path:
export mypath=$dirname{$PWD}This is unfortunately does NOT reach your goal: to get the full path of the script location. It turns out the full path of your current dir when you invoke the script.
A tested solution is provided by someone's posts to this thread:
#!/bin/bash
#==========================
# bash - find path to script
#==========================
abspath=$(cd ${0%/*} && echo $PWD/${0##*/})
# to get the path only - not the script name - add
path_only=`dirname "$abspath"`
#display the paths to prove it works
echo $abspath
echo $path_only
Another interesting article about this topic can be found at google code
4 comments:
This method breaks when invoke the script by "source". In the latest bash, a fix could be:
change the ${0%/*} from
abspath=$(cd ${0%/*} && echo $PWD/${0##*/})
to ${BASH_SOURCE[0]%/*}
There is still a problem with the above comment. Once we invoke "source xx", you will get a cd error. Here is a complete solution:
ME=${BASH_SOURCE[0]}
if [[ ! $ME =~ "\/" ]];then
ME="./"$ME
fi
mypath=$(cd ${0%/*} && echo $PWD/${0##*/})
mypath=`dirname ${mypath}`
You could also try this:
http://fritzthomas.com/open-source/linux/384-how-to-get-the-absolute-path-within-the-running-bash-script/
alternative:
echo `dirname $0 | xargs readlink -e`
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